Finding The Tension force with different angles

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Homework Help Overview

The problem involves a mass hanging from a ceiling supported by two strings at different angles, specifically 30 degrees and 65 degrees. The mass is given as 20 lb, and the participants are working to find the tension forces in the strings.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss setting up equations based on the equilibrium of forces in both the x and y directions. There is an attempt to isolate the tension forces T1 and T2 using trigonometric relationships.

Discussion Status

Some participants have provided guidance on rewriting equations for clarity and substitution. There are indications of confusion regarding the calculations, particularly in solving for the tensions, and multiple interpretations of the equations are being explored.

Contextual Notes

Participants note the distinction between weight and mass, and there is a mention of a missing force in the equations. The discussion reflects an ongoing exploration of the problem setup and the relationships between the variables involved.

Ashleyz
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Homework Statement


I have done all the physics for this problem which I'll detail below. I am only having trouble in doing the simple math to single out the t1 or t2.

A mass is hanging from a ceiling. It is supported by two strings which both are attached above to the ceiling. String 1 is at an angle of 30. String 2 is at an angle of 65. While the
mass is 20 lb. ( in the center)





Homework Equations

Ma = 0 in both the x and y directions.



The Attempt at a Solution


left T (T1) =30 degrees

right T (T2) = 65 degrees.

ok, here are my equations that I get to:

X: T2cos(65) - T1cos(30) = 0

Y: T2sin(65) + T1sin(30) = 0

now I just need to solve for, say, T1 in the x dierection and use that new eq. to
pluge into Y. Right?
 
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The 20 pounds is the value of the weight of the hanging mass; it is not the mass. In your last equation in the y direction, you are missing a force.
 
right. I am missing -w. Sorry about the mistake.

Now what of the T that I need to solve for. I have Solved for the T in my
x and y equation and get bad nasty answers.
 
First plug in the value for cos 65, sin 65, etc. Then solve the 2 equations with the 2 unknowns as you see fit.
 
Do you mean this:

I'll take the x eq. and solve for t1.

I get T1 = T2cos(65) / cos (30)

now I can take this eq. for T1 and plug it in for T1 in the y eq?
 
It will be a lot easier if you rewrite your first equation as T1= T2(.423)/.866 = 0.49T2. Rewrite the 2nd equation in the same manner, then do the substitution.
 
PhanthomJay said:
It will be a lot easier if you rewrite your first equation as T1= T2(.423)/.866 = 0.49T2. Rewrite the 2nd equation in the same manner, then do the substitution.

I see.

T1 = T2(.49)

T2 = 21.74lb + T1(.54) I divided .92 into lbs., think you can do that.

now ill put T2 in the T1 eq. Right?
 

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