Finding the time evolution of a state

Kyrios
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Homework Statement



1) Using energies and eigenstates that I've worked out, find time evolution ψ(t) of a state that has an initial condition ψ(0) = <br /> \begin{pmatrix}<br /> 1 \\<br /> 0\\<br /> \end{pmatrix}<br />

2) Find the expectation values < Sy> and <Sz> as a function of time.


Homework Equations



The Hamiltonian is H = \alpha (B_x S_x + B_y S_y + B_z S_z)


The energies that I worked out were the eigenvalues:

\lambda_1= \frac{ \alpha \hbar B_x }{2}

\lambda_2= - \frac{ \alpha \hbar B_x }{2}


The eigenstates were the eigenvectors
<br /> \begin{pmatrix}<br /> 1 \\<br /> 1\\<br /> \end{pmatrix}<br />

and

<br /> \begin{pmatrix}<br /> 1 \\<br /> -1\\<br /> \end{pmatrix}<br />

The Attempt at a Solution



I tried using the time evolution operator
U(t)= exp( \frac{ -i H t}{\hbar} )

I ended up with something that looks like this:

\psi(t) = A exp( \frac{ -i \alpha B_x t}{2} ) (1, 1) + B exp( \frac{ i \alpha B_x t}{2} ) (1, -1)


But I'm really unsure of where to go from here, or whether this is even right.
 
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Just check if your answer satisfies the inital condition and determine the constants A and B from normalization.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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