Finding the voltage using J and F? help T_T

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To find the voltage required to store 2.00 J in a 10.0 µF capacitor, the relevant equation is PE = 0.5 CV². Rearranging this equation to solve for voltage gives V = sqrt(2 * PE / C). Substituting the values, V = sqrt(2 * 2.00 J / 10.0 µF) results in a voltage of 632 V. It's important to clarify that PE refers to potential energy, not current density J. Understanding this distinction is crucial for solving the problem correctly.
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Homework Statement



If 2.00 J are to be stored in a 10.0uF capacitor, what voltage must be applied to it??

Homework Equations


PE= .5 CV^2


The Attempt at a Solution



The answer is 632V...but I don't know how to get this answer...T_T

please help ASAP !
 
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You need to simply solve for V in your relevant equation, giving you

V=sqrt(PE*2/C)

Make sure not to confuse your PE with current density J. Reading your heading I made the assumption you had a question about current density.
 

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