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Finding the voltage

  1. Feb 14, 2007 #1
    1. The problem statement, all variables and given/known data


    Loop 1 is the far left loop with mesh current i_1. Loop 2 is the right one with mesh current i_2. BOTH CURRENTS ARE GOING IN THE CW direction.

    3. The attempt at a solution


    This got cut off while scanning... but I multiplied i_2 with 12kOhms to get my V0.

    Heres my work. Can you verify if this is correct, I am having doubts.
    Last edited: Feb 14, 2007
  2. jcsd
  3. Feb 15, 2007 #2
    Yeah it's correct.
  4. Feb 15, 2007 #3
    Are you sure? My online system said it was incorrect. I came to have (- .198) * 12 = -2.37

    I tried both +2.37 and -2.37, and it said it was incorrect.
  5. Feb 15, 2007 #4
    I don't see any mistakes on your part. But I got a slightly different answer in v0 = (-0.19853)*12 = -2.3824A.
  6. Feb 15, 2007 #5
    Heh, so little makes a difference :)

    -2.38 it is...
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