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Finding the voltage

  • Thread starter ravenprp
  • Start date
  • #1
74
0

Homework Statement



http://img101.imageshack.us/img101/2585/74785719qc4.jpg [Broken]

Loop 1 is the far left loop with mesh current i_1. Loop 2 is the right one with mesh current i_2. BOTH CURRENTS ARE GOING IN THE CW direction.


The Attempt at a Solution



http://img291.imageshack.us/img291/8002/50402522dx3.png [Broken]

This got cut off while scanning... but I multiplied i_2 with 12kOhms to get my V0.

Heres my work. Can you verify if this is correct, I am having doubts.
 
Last edited by a moderator:

Answers and Replies

  • #2
133
0
Yeah it's correct.
 
  • #3
74
0
Are you sure? My online system said it was incorrect. I came to have (- .198) * 12 = -2.37

I tried both +2.37 and -2.37, and it said it was incorrect.
 
  • #4
161
0
I don't see any mistakes on your part. But I got a slightly different answer in v0 = (-0.19853)*12 = -2.3824A.
 
  • #5
180
0
Heh, so little makes a difference :)

-2.38 it is...
 

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