Finding the volume of a cube with 1 Joule

AI Thread Summary
To find the edge length L of a cube containing 1 Joule of thermal energy in interstellar space, the user calculated the pressure and volume using the ideal gas law. They derived the volume as 8.05x10^15 m^3 based on the energy equation Eth = 3pV. Additionally, they calculated the average kinetic energy of a hydrogen atom at 3 K, resulting in 6.21E-23 J per atom. By determining the number of atoms required to reach 1 Joule, they found approximately 1.61E22 atoms in a volume of 1.61E22 m^3, leading to an edge length L of about 2.52E7 m. The calculations appear consistent, but verification of each step is recommended for accuracy.
pdonovan
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Homework Statement


Interstellar space, far from any stars, is filled with a very low density of hydrogen atoms (H, not ). The number density is about and the temperature is about 3 K.

What is the edge length L of an LxLxL cube of gas with 1.0 J of thermal energy?

I found:
P = 4.14x10-17Pa
Vrms = 273m/s


Homework Equations



Eth = 3NKbT = 3nRT = 3pV

The Attempt at a Solution



Eth = 1J

Eth = 3pV = 3(4.14x10-17)V
--> V = 8.05x1015

Is this the correct answer or is my math wrong somewhere? Thank you for any input!
 
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The average kinetic energy of an atom in a gas at temperature T is,

E = 3/2kT

k = 1.38E-23 J/K
T = 3 degrees K

E = 6.21E-23 J

If the density of atoms was 1/m^3 then X*6.21E-23 J = 1 J ?

X=1.61E22 atoms in 1.61E22m^3 of space. The cube root of 1.61E22m^3 = 2.52E7 m = L ?
 
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