Finding the Weight of a Rope and Bucket

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Homework Statement



A rope is 5 meters long and hangs over the edge of a well. It has a bucket of water weighted 20 kilograms attached to one end. For Simplicity, use g=10N/kg

Suppose the rope has a uniform density of \rho = 1kg/m

Homework Equations



W=\int F(x)xdx


The Attempt at a Solution



I could not figure out what the force would be I would think it would be (Mrope+Mbucket)g
Mass of the rope would be (\rho)(v)=Mrope
 
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Welcome to PF!

Welcome to PF! :smile:

(have a rho: ρ and an integral: ∫ :wink:)

Does the question ask for the work done in raising the bucket 5 m ?

If so, remember that the rope doesn't rise 5 m … it stops as it gets to the top.

Use work done = change in PE. :wink:
 
I know I can do change in PE but this is for my calculus and my teacher wants me to use calculus I did some more work and found this so far. F(y)=(Mrope+Mbucket) Mrope=\rhov. Now I have to find change in y for that I got (5-y) Now my equation for work is the integral from 0 to 5 of (\rhoy+20)(5-y)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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