werson tan said:to find the velocity , i have 2(1.6)(50) = (20^2)- (u^2) , u = 15.5m/s
but i have problem of finding the time ,
why i can't use the eq of s= ut +1/2(a)(t^2) ,
50 = 0+1/2(1.6)(t^2) , t= 8s ,
50 = 15.5(1) +1/2(1.6)(t^2) , t= 6.56s
the given time = 2.8s
To calculate time and velocity, you can use the formula v = d/t, where v is velocity, d is distance, and t is time. Rearrange the formula to solve for t by dividing d by v.
Average velocity is the total displacement divided by the total time, while instantaneous velocity is the velocity at a specific moment in time. Average velocity gives an overall picture of an object's motion, while instantaneous velocity shows the object's velocity at a particular point.
Acceleration is the rate of change of velocity over time. So, the longer an object accelerates, the more time it takes for it to reach a certain velocity. Additionally, a greater acceleration will result in a higher velocity in the same amount of time.
Yes, time and velocity can be negative in certain situations. For example, if an object is moving in the opposite direction of a chosen positive direction, its velocity will be negative. Similarly, if an object is slowing down, its acceleration will be negative.
To predict an object's future position, you can use the formula d = vt, where d is the distance, v is the velocity, and t is the time. This formula assumes that the object maintains a constant velocity and does not accelerate or decelerate. If the object is accelerating, you will need to use a different formula, such as d = v0t + 1/2at2, where v0 is the initial velocity and a is the acceleration.