Finding Time when throwing an object up

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To solve the problem of a ball thrown from a 55-meter building with an initial speed of 35 m/s, the correct approach involves calculating the maximum height the ball reaches before falling back down. The equations of motion, specifically d = v0t + 1/2at², can be utilized to determine the time taken to reach the peak height and the subsequent time to fall back to the ground. The total time to hit the ground is the sum of the ascent and descent times. Using the acceleration due to gravity (9.8 m/s²) is crucial in these calculations. Ultimately, the solution requires careful application of kinematic equations to find the total time of flight.
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Homework Statement



Standing on the top ledge of a 55 meter high building you throw a ball straight up with an initial speed of 35 m/s. How long, to the nearest second, does it take to hit the ground?

Homework Equations



v= at + vo

The Attempt at a Solution



i think I am using the wrong equation...
X= 55
V= 35
a=9.8
t=?
 
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Try using: d=vot +1/2at2
 
Maybe if you figured how high it would go you could figure how long it will take to hit the ground from that total height? And then that added to how long it took to get to that height would be your total time wouldn't it?
 
LowlyPion said:
Maybe if you figured how high it would go you could figure how long it will take to hit the ground from that total height? And then that added to how long it took to get to that height would be your total time wouldn't it?

Right, you would need, 2ad = vf2-vi2
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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