Finding Unknowns in Vector Equations

  • Thread starter Thread starter nickh89
  • Start date Start date
  • Tags Tags
    Vectors
AI Thread Summary
To solve for the unknowns a and b in the vector equation aA + bB + C = 0, where A = (5.00, -7.00), B = (-7.00, 2.00), and C = (27.0, 20.0), the components of the vectors can be plugged into two equations. This results in the system of equations: 5a - 7b + 27 = 0 and -7a + 2b + 20 = 0. With two equations and two unknowns, a and b can be determined. It is clarified that A should be interpreted as A = (5.00, -7.00) rather than A = -2. Properly setting up the equations allows for a straightforward solution.
nickh89
Messages
2
Reaction score
0

Homework Statement


If A= (5.00 -7.00 ) units, B= (-7.00 + 2.00 ) units, and C= (27.0 + 20.0 ) units, determine a and b such that aA+ bB + C = 0.


Homework Equations


What I did to try and figure this out was solve for a and got the result of
a = -bB - C/ A

The Attempt at a Solution



What I did to try and solve this equation was plug that in for a, and take all the magnitudes of the vectors that are stated above but when i proceeded to do that everything would just cancel out when attempting to solve for b at that point. Any help would be great thank you.
 
Physics news on Phys.org
You can't divide vectors like that. Secondly i take it that A=(5.00 , -7.00) is what you meant right? The way you have written it now suggests A=-2.

Plugging the components of the vectors into the vector equation will give you two "normal" equations. Since you have two unknowns and two equations you can solve a and b.

<br /> \begin{align}<br /> &amp;5a-7b+27=0<br /> \\<br /> &amp;-7a+2b+20=0<br /> \end{align}<br />
 
yes it was A = (5i, -7j), and thank you very much for the help.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top