Finding values of x where the infinite geometric series converge

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Homework Help Overview

The discussion revolves around determining the values of x for which an infinite geometric series converges, specifically the series represented by (2+x)+(2+x)^2+(2+x)^3 + ...

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the condition for convergence, noting that the common ratio is (2+x) and exploring the inequality -1 < 2 + x < 1. Questions arise regarding specific values of x, such as x = 0, and whether the initial interpretation of the convergence range is correct.

Discussion Status

Some participants express uncertainty about the correctness of the derived range for x, while others provide hints and affirmations. There is an acknowledgment of potential misreading of the inequality, but no clear consensus has been reached on the final interpretation.

Contextual Notes

Participants are navigating through the implications of the convergence criteria and are reflecting on their understanding of the series without providing definitive solutions.

meeklobraca
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Homework Statement


(2+x)+(2+x)^2+(2+x)^3 + ...


Homework Equations







The Attempt at a Solution



Ive found that the l r l < 1

the r of this equation is (2 + x)

so we have -1 < 2 + x < 1

The values of x where the series coverges is -3 < x < -1

Is this correct?

Thanks!
 
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hmm …

meeklobraca said:
(2+x)+(2+x)^2+(2+x)^3 + ...

Ive found that the l r l < 1

the r of this equation is (2 + x)

so we have -1 < 2 + x < 1

The values of x where the series coverges is -3 < x < -1

Is this correct?

Thanks!

:smile: :smile: :smile: :smile:

Hint: does it converge for x = 0? :wink:
 
meeklobraca said:

Homework Statement


(2+x)+(2+x)^2+(2+x)^3 + ...


Homework Equations







The Attempt at a Solution



Ive found that the l r l < 1

the r of this equation is (2 + x)

so we have -1 < 2 + x < 1

The values of x where the series coverges is -3 < x < -1

Is this correct?

Thanks!

Looks good to me:approve:
 


tiny-tim said:
:smile: :smile: :smile: :smile:

Hint: does it converge for x = 0? :wink:



No I don't think so?

Does your laughing faces mean I got it right? lol
 
i need glasses

meeklobraca said:
No I don't think so?

Does your laughing faces mean I got it right? lol

oh dear … I read a -1 as a 1. :redface:

Yes … sorry, meeklobraca … you got it right! :biggrin:
 

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