- #1
hungryhippo
- 10
- 0
How would you approach a question where you're given a curve in terms of a scalar equation, and asked to find the orthogonal projection of this curve in the yz-plane
You know that the curve is the intersection of the surfaces of:
x=y^2+z^2 --1
x-2y+4z=0 --2
From here, I would just substitute equation 1 into 2 for x, to find the resulting curve
I know that a yz-plane indicates that the x-coordinate will always be 0 , so (0,y,z)
For scalar projections, you can find it as just
(a) dot (b) / (length of a)
I'm not sure if what I'm thinking so far is correct, and extremely unsure on the projection part.
I really need help on this
Thanks in advance for any advice
You know that the curve is the intersection of the surfaces of:
x=y^2+z^2 --1
x-2y+4z=0 --2
From here, I would just substitute equation 1 into 2 for x, to find the resulting curve
I know that a yz-plane indicates that the x-coordinate will always be 0 , so (0,y,z)
For scalar projections, you can find it as just
(a) dot (b) / (length of a)
I'm not sure if what I'm thinking so far is correct, and extremely unsure on the projection part.
I really need help on this
Thanks in advance for any advice