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Finding Vector Projections

  1. Oct 17, 2009 #1
    How would you approach a question where you're given a curve in terms of a scalar equation, and asked to find the orthogonal projection of this curve in the yz-plane

    You know that the curve is the intersection of the surfaces of:

    x=y^2+z^2 --1
    x-2y+4z=0 --2

    From here, I would just substitute equation 1 into 2 for x, to find the resulting curve

    I know that a yz-plane indicates that the x-coordinate will always be 0 , so (0,y,z)
    For scalar projections, you can find it as just

    (a) dot (b) / (length of a)

    I'm not sure if what I'm thinking so far is correct, and extremely unsure on the projection part.

    I really need help on this :eek::confused:

    Thanks in advance for any advice
     
  2. jcsd
  3. Oct 17, 2009 #2

    Dick

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    Science Advisor
    Homework Helper

    You are probably just over thinking this whole thing. Once you've found a yz curve by eliminating x, you are done, right? Projection into the yz plane just means ignore the x value. You don't need a projection formula for this case.
     
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