Finding velocity of elastic collision with angles

AI Thread Summary
In an elastic collision between a red ball and a blue ball, both with a mass of 40g, the blue ball initially travels at 4 m/s in the x-direction while the red ball is at rest. After the collision, the blue ball moves at +35 degrees and the red ball at -55 degrees. To solve for their speeds post-collision, both conservation of momentum and conservation of kinetic energy must be applied, treating momentum as a vector equation with separate x and y components. The initial attempt to use conservation of kinetic energy was noted, but the angles must be incorporated into the momentum equations for accurate results. Properly setting up these equations will yield the final velocities of both balls.
Valenti
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Homework Statement


A red ball and blue ball are sliding on a frictionless surface, each ball has a mass of 40g. They collide in an elastic collision. Initially the red one is at rest and the blue one is traveling in the x direction with a speed of 4 m/s. After the collision the blue one is traveling in the direction +35 degrees, with the red one traveling in the direction ‐55 degrees. Using conservation of energy and momentum find the speed of each puck after the collision

Homework Equations


Conservation of momentum: M1Vi1+ M2Vi2 = M1Vf1 + M2Vf2
Conservation of kinetic energy: 1/2MVi12 + 1/2MVi22 = 1/2MVf12 + 1/2MVf22

The Attempt at a Solution


Started using conservation of kinetic energy and got 4 = Vf1 + Vf2
Wasn't sure how to isolate V plugged it into Conservation of momentum factored out m setting Vf1 + Vf2 to 4
0.04kg(4m/s)+ 0 = 0.04kg (4)
It didn't seem to do anything and I'm not exactly sure where I'm supposed to use the angles
 
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Valenti said:
Started using conservation of kinetic energy and got 4 = Vf1 + Vf2

Good start.

To use the conservation of momentum equation you have take into account that it's a vector equation. Which means it's really two equations. One in the x-direction, one in the y-direction. That's where those angles will enter.
 
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