Finding vs in a Circuit with v2=1000i2 and i2=5 mA

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The circuit analysis involves determining the voltage source vs given the equations v2 = 1000i2 and i2 = 5 mA. By converting 5 mA to 0.005 A, v2 is calculated as 5000 V. The relationship v2 = 5v1 leads to v1 being determined as 1000 V. Since v1 is connected across vs, it follows that vs equals 1000 V. The discussion clarifies that the units used for current do not affect the calculations, as long as they are consistently converted.
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Homework Statement



For the circuit shown, if v2 = 1000i2 and i2 = 5 mA, determine vs.

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Homework Equations



5 mA = 0.005 A
P = v_{2}i

The Attempt at a Solution



P = v_{2}i

v_{2} = \frac{P}{I} = \frac{5}{0.005} = 1000 V

v_{2} = 5v_{1}

v_{1} = \frac{v_{2}}{5} = \frac{1000}{5} = 200 V

What I am having problems with is v_{s} is a independent voltage source so I am not sure what to do.
 
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Hi Killer. I'd like to help but I don't understand the symbols in your diagram. What is the circle marked Vs - a voltage source or a Voltmeter? Are V1 and V2 meters? What about the diamond with an arrow?
 
Well that's all the question showed but I am certain that the circle marked Vs is a independent voltage source and the diamond with an arrow is a dependent source (voltage-controlled) and I think the squares are a circuit terminal elements I don't think it is important what they are just what way the current goes through them (like through the positive or negative side first to determine + or - current.
 
Very strange - I've never seen anything like it before.
Anyway, it says V2 = 1000*i2 and i2 = 5, so V2 = 5000.
V2 is supplied by the 5V1, so we have 5V1 = 5000 and V1 = 1000 Volts.
V1 is the connected across Vs, so Vs = V1 = 1000 Volts.
 
Ok. Would it matter if i2 is in mA not A or would that not effect it?
 
Good catch! Change my 5 to .005.
 
Ok thanks for the help.
 
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