- #1
You need to show some attempt first.shahrilmajid said:Homework Statement
View attachment 233203
Homework Equations
fd cos theta
The Attempt at a Solution
Finding the work done. Please anybody help me[/B]
shahrilmajid said:Constant velocity, a=0
f=ma , mean total f in x and y direction is totally 0
on y componen = N-W+Fsin teta
x component = fk + Fsin teta
please check
Work done by worker pulls is a measure of the force that a worker applies in order to move an object. It is calculated by multiplying the force applied by the distance the object moves in the direction of the force.
The work done by worker pulls is calculated by multiplying the force applied by the distance the object moves in the direction of the force. This can be represented by the formula W = F * d, where W is the work done, F is the force applied, and d is the distance the object moves.
The unit of measurement for work done by worker pulls is joules (J). This is the standard unit for work in the International System of Units (SI).
The angle of the pull does not directly affect the work done by worker pulls. The work done is only affected by the component of the force that is in the direction of motion. Therefore, the angle of the pull will only affect the work done if it changes the direction of the force applied.
Some real-life examples of work done by worker pulls include pushing a shopping cart, pulling a suitcase, lifting weights, and using a hand-operated lever. Essentially, any time a person applies a force to move an object, work is being done by worker pulls.