Finding work done by worker pulls

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Homework Help Overview

The discussion revolves around calculating the work done by a worker pulling an object, with a focus on the forces involved and their components. The subject area includes concepts from mechanics, particularly relating to forces and work.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the need to show attempts at solving the problem, including listing forces and resolving them into components. Some participants provide equations and express concerns about the approach taken regarding the balance of forces in different directions.

Discussion Status

The discussion is ongoing, with participants providing feedback on the attempts made. There is an emphasis on ensuring that the forces are represented correctly and that the equations reflect the physical situation accurately.

Contextual Notes

Participants note the importance of showing work and the potential need for clarity in the representation of forces and their components. There is an indication that assumptions about the directions of forces may need to be reconsidered.

shahrilmajid
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Homework Statement


45186762_10156129905398520_2106908980285538304_n.jpg


Homework Equations


fd cos theta

The Attempt at a Solution


Finding the work done. Please anybody help me[/B]

 

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shahrilmajid said:

Homework Statement


View attachment 233203

Homework Equations


fd cos theta

The Attempt at a Solution


Finding the work done. Please anybody help me[/B]
You need to show some attempt first.
List the forces, creating symbols to represent them (like, N for normal force).
Resolve into vertical and horizontal components.
Write equations relating these.
 
Constant velocity, a=0
f=ma , mean total f in x and y direction is totally 0
on y componen = N-W+Fsin teta
x component = fk + Fsin teta

please check
 
shahrilmajid said:
Constant velocity, a=0
f=ma , mean total f in x and y direction is totally 0
on y componen = N-W+Fsin teta
x component = fk + Fsin teta

please check

1) It's very unlikely that the forces in two orthogonal directions are calculated with the same trigonometric function
2) In your x-direction balance both forces are pointing in the same direction
 

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