Finding x: Graphical Solution to sin(x/2)=x/4

  • Thread starter Thread starter garyng2001hk
  • Start date Start date
AI Thread Summary
To solve the equation sin(x/2) = x/4, a graphical method is recommended. By plotting the curves of y = sin(x/2) and y = x/4, the intersection points reveal the solutions for x. The solutions are found at x = 0 and approximately x = ±3.8. An alternative approach involves rearranging the equation to sin(x/2) - x/4 = 0 and identifying where the curve crosses the x-axis, confirming three crossings at these values. The analysis indicates no additional intersections beyond these points.
garyng2001hk
Messages
5
Reaction score
0

Homework Statement


Solve for x.

Homework Equations


Given sin(x/2) = x/4.

The Attempt at a Solution


no idea. the question gives a hint: use graphical method.
 
Physics news on Phys.org
You just have to graph y=sin(x/2) and y=x/4 and find the intersection pts.
 
your solution comes as mentioned below

1. draw a curve of x vs sin(x/2)
2. draw a second curve of "x vs x/4"

The solution for x is where both the curves intersect. these are two points

x=0
and
x=3.8

you can find the resultant chart in attached file.
 

Attachments

Plotting \sin(x/2) vs. x and x/4 is the way to go indeed.

You can plot this another way also.
Rearranging

sin(x/2) = x/4

to

sin(x/2) - x/4 = 0

and plotting where the curve crosses the x-axis is also another way. It crosses three times. At exactly x=0 and at x equals approximately -3.8 and approximately +3.8.
Close up you see the "zero-crossings" of the x-axis at {-3.8,0,3.8} and if you zoom out you see the curve does not cross at any other points (as far as we can see).
 

Attachments

  • close.GIF
    close.GIF
    3.3 KB · Views: 574
  • far.GIF
    far.GIF
    3.3 KB · Views: 563
Here it is from very far away.
 

Attachments

  • veryfar.GIF
    veryfar.GIF
    3 KB · Views: 566
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top