Fireing projectile from north pole to equator

AI Thread Summary
To fire a projectile from the North Pole to the equator, one must consider the Earth's curvature and gravitational variations, complicating the calculations. A suggested launch angle of 45 degrees with a muzzle velocity of 9401 m/s seems impractical. The problem involves solving complex non-linear differential equations, particularly if air friction and Earth's surface deviations are included. A simpler approach could involve achieving a trajectory similar to a circular orbit by firing horizontally at the appropriate orbital velocity. Ultimately, the challenge lies in accurately modeling these physical factors for a successful launch.
greaser
Messages
2
Reaction score
0
I am trying to find what velocity and angle of launch is required for a projectile to be fired from the North pole and land somewhere on the equator. I was thinking 45 degrees with muzzle velocity 9401m/s but that sounds ridiculous. Also how much time would it be in the air for?
 
Physics news on Phys.org
Looks to me like a very difficult problem, probably involving solving a nasty non-linear differential equation.

IF it were a matter of finding the angle and initial velocity of a flat plane, with constant gravitational acceleration, a distance equal to the distance from the north pole to the equator, then it would be relatively simple. However, if you REALLY mean "north pole to the equator" you will have take into account the curvature of the Earth and the fact that you are firing the projectile around 1/4 of that curvature. Your trajectory will be high enough that you will have to take into account the fact that the gravitational force falls off as 1/r2.
 
I think this problem becomes simple if we may neglect air friction and any deviations of the Earth's surface from being a sphere.
Because in this case, an orbit will do which is 'infinitesimally close' to a circular orbit. Which means: fire horizontally with circular orbit velocity.

I'm afraid we must *not* neglect those...
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Let there be a person in a not yet optimally designed sled at h meters in height. Let this sled free fall but user can steer by tilting their body weight in the sled or by optimal sled shape design point it in some horizontal direction where it is wanted to go - in any horizontal direction but once picked fixed. How to calculate horizontal distance d achievable as function of height h. Thus what is f(h) = d. Put another way, imagine a helicopter rises to a height h, but then shuts off all...

Similar threads

Back
Top