First ODE of an absolute value

[sydneyw]

so I understand the basic premise of differentiating a first ODE, or I thought I did. I have the equation y'-y=abs(x-1). I have no idea of how to go about this. Can someone walk me through how to do this? I'm attempting to study for a test and this is one of the practice questions he gave us so I feel as though I'm in some serious trouble if I don't learn how to do this! Thank you much.

 

[LCKurtz]

Can you solve $y'-y=x-1$? Can you solve $y'-y=1-x$? These are the two cases you have depending on whether $x>1$ or $x<1$. Solve them separately.

 

[HallsofIvy]

First, you don't want to "differentiate" the ODE, you want to integrate it.

And the simplest way to handle the absolute value is to use the definition. If $x\ge 1$, x- 1 is non-negative so |x- 1|= x- 1 and your differential equation becomes dy/dx- y= x- 1.
If x< 1, x- 1 is negative so|x- 1|= -(x- 1)= 1- x and your differential equation becomes dy/dx= 1- x.

Integrate those to get two general solutions, one valid for x> 1, the other valid for x< 1.