First Order Circuit: Replacing Inductor & Current Source

AI Thread Summary
Replacing the inductor with a short circuit results in a zero voltage across it, which means current flows through the 3k resistor. The current source remains active, demanding a specific current flow, regardless of the voltage across it. The 2k and 6k resistors can be removed since the voltage across them is zero, leading to no current through them. The current source continues to draw its specified current, in this case, 5mA. Ultimately, this setup confirms that there is 2mA of current traveling through the inductor.
Jebus_Chris
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I'm not sure what happens when you replace the inductor with a short circuit. The current source is what throws me off.

One thought I had was that you can remove the 6 and 2 kohm resistors, but then I don't know what ahppens to the current source.
http://imgur.com/lks7y
Thanks
 
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Everything you've said is right. The voltage across the inductor being 0 also means some current is flowing through the 3k resistor. The current source demands a certain current flow, so KCL should give you the inductor's steady current.
 
So then are you saying that you remove the current source as well since the voltage around it is zero?
 
Jebus_Chris said:
So then are you saying that you remove the current source as well since the voltage around it is zero?

The question is designed to trick your intuition. A current source can pull any amount of current no matter what the voltage across it is, including 0 volts.

What you've said about the 2k and 6k resistors is correct -- the voltage across them is zero so Ohm's law gives zero current through them. The current source continues to draw 5mA no matter what.
 
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Ok, so then you're saying that there is 2mA of current traveling up [i(0) = -2] through the inductor?
 
Yes, that's it.
 
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