Ok, lets say I have a first order circuit with i_s = Acos(wt+phase) (like in the pic).(adsbygoogle = window.adsbygoogle || []).push({});

I'm having problem with the private solution, lets say I pick my private solution like this:

i_p = Bcos(wt + phase) = Ccos(wt) + Dsin(wt) (right?)

After I place this i_p in the equation I come up with this:

f[C,D]*cos(wt) + g[C,D]*sin(wt) = Acos(wt+phase) (right?)

Can I say

f[C,D]*cos(wt) + g[C,D]*sin(wt) = Acos(wt)?

I mean, How do I come up with C and D?

10x in advance.

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# Homework Help: First Order Circuits

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