First Principles-( ε-δ methods) proof.

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(X^2+1)/(X^3-9) → -1/4 as x → 1

(without using algebra of limits. Also constructing δ explicitly).

I have attempted this question but to no avail,

I start like this:

= |(X^2+1)/(X^3-9)+1/4|

= (4(X^2+1)+X^3-9)/ 4(X^3-36)

try factorisation but am unsuccessful.

Anybody lend a helping hand?
 
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manooba said:
(X^2+1)/(X^3-9) → -1/4 as x → 1

(without using algebra of limits. Also constructing δ explicitly).

I have attempted this question but to no avail,

I start like this:

= |(X^2+1)/(X^3-9)+1/4|

= (4(X^2+1)+X^3-9)/ 4(X^3-36)

try factorisation but am unsuccessful.

Anybody lend a helping hand?
Expand (multiply out) the terms in the numerator. Then collect like terms and factor the result.

That's a start.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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