Flow through parallel pipes with different diameters

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SUMMARY

The discussion focuses on analyzing fluid flow through parallel pipes of different diameters under laminar conditions. The governing equations include the Reynolds transport theorem, conservation of mass, and momentum equations. Key insights reveal that while pressure drops across both pipes remain equal, flow rates differ due to varying cross-sectional areas. The application of Bernoulli's equation is crucial for understanding the relationship between pressure and velocity in this scenario.

PREREQUISITES
  • Understanding of Reynolds transport theorem
  • Familiarity with Bernoulli's equation
  • Knowledge of laminar flow characteristics
  • Basic principles of fluid dynamics
NEXT STEPS
  • Study the application of Reynolds transport theorem in multi-pipe systems
  • Explore the implications of varying cross-sectional areas on flow rates
  • Learn about pressure drop calculations in parallel pipe configurations
  • Investigate the effects of fluid properties on laminar flow behavior
USEFUL FOR

Fluid dynamics engineers, mechanical engineers, and students studying fluid mechanics will benefit from this discussion, particularly those interested in the analysis of flow in parallel piping systems.

berkanozturk
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Homework Statement



Consider an apparatus design in which two tubes of different diameters are connected in parallel to each other.
The flow is steady and fully developd in both tubes. Do your analysis regarding
a)the governing differential equations for the case that in both tubes laminar flows occur.

Homework Equations



Asked

The Attempt at a Solution


Hello everyone,
For one pipe, we can simply use Reynolds transport theorem for a differential volume, and then get the related conservation of mass and momentum equations for 1 PIPE. However, when there are two pipes, how should I relate it? I could not solve it, hope you can help me. thanks for reading so far...

best regards
berkan
 
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Assuming the pipes are connected to the same manifolds (headers), then the pressure drops across the pipes (lengthwise) would be the same. The flow rates would be different because the flow resistance would be different (including the cross-sectional areas).

The electrical analog is two resistors in parallel. Both resistors have the same potential drop across their terminals, but the current (charge flow rate) is different.
 
using bernoullli equation;

P/p + 1/2(V)^2=constant, (P:pressure, p:density, V:velocity)

lets say pipe1 is carrying the main stream and pipe2 and pipe3 are the parallel pipes with different diameters,

then it must be;

P1/p + 1/2(V1)^2 = P2/p + 1/2(V2)^2 = P3/p + 1/2(V3)^2

Remember;

Q=A*V

for different diameters crossectional area difference also changes V (as i know, correct me if i m wrong), so;

P2=P3 can not be achieved.

when it comes to may be

P1=P2 or P1=P3 ?

it depends on V1, V2 and V3 again. the same V will result the same P if material properties (heat, density etc.) and level of pipes not changed.
 
Last edited:

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