Flowmetry: find height of fluid in cylinder

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SUMMARY

The discussion focuses on calculating the height of fluid in a cylinder with varying diameters while being filled and emptied simultaneously. The flow rate into the cylinder is known, while the outflow rate, Qout, is determined using the equation Qout = A * Cd * SQRT(2 * g * h), where A is the area of the outlet and g is the acceleration due to gravity. The problem involves solving a first-order differential equation for the fluid height over time, with the initial condition set at time=0 seconds where the height change is zero.

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Homework Statement


A cylinder with varying diameters is being filled and emptied at the same time. The time is measured.
I know Flow rate into cylinder. How do I find the height of fluid in the cylinder at a particular time?

The diameter of the hole is 0.005m.
The diameter of the bottom of the cylinder is 4cm.
The diameter of the top of the cylinder is 6cm.

I don't know Qout nor height, h.

Homework Equations


Qout= A. Cd. SQRT(2.g.h)

The Attempt at a Solution


At time=0 sec: change in height of fluid is 0
At time=1 sec: change in height of fluid is (Qin-Qout)/Area of cylinder
 
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You have a first-order differential equation to solve:
##d\over dt ## holdup = Qin - Qout
where
holdup is a function of h(t)
and
Qout is a function of h(t)

Your initial condition (if what you write is correct) is ##d\over dt ## holdup = 0 at t=0

Substitute the appropriate expressions for holdup(h) and Qout(h)
 

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