Fluid Dynamics: Answering Pressure in a Full Tank

AI Thread Summary
The discussion revolves around calculating the lowest pressure in a full tank of water when a valve at the bottom is opened while the top valve remains closed. As the water drains, a vacuum forms inside the tank, potentially leading to vaporization due to low pressure. The pressure can be calculated using the formula 14.7 psi minus the product of water density, gravitational acceleration, and the height of the water column. For a height of 30 feet, the pressure drops significantly, but at 40 feet, the minimum pressure falls below the vapor pressure of water, making the scenario unfeasible. This highlights the importance of considering vapor pressure in fluid dynamics calculations.
shannajo03
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I understand the concept of this question, I think, but I don't know how to go about getting an answer.

A tank is completely full of water with no air. A valve at the bottom is opened, while one on top remains closed. What is the lowest pressure that the tank will reach. From valve to valve the height is 30ft.

I understand that as the water drains, it will pull a vacuum inside the tank, which will eventually collapse at a low enough pressure. I also know that the water will vaporize at some point due to the lack of pressure in the tank, but I don't know if they want the vapor pressure (no temp was given) or if there is some calculation to do.

Any guidance is appreciated!
 
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For anyone who is wondering, I found out the answer. You assume atmospheric pressure pushes up into valve B, so the pressure in the tank is 14.7psi-(rho)gh where rho is the density of water, g is gravitational accel. (32.2ft/s^2), and h is 30ft. The point was that on the second part (h=40ft), the minimum pressure is below the vapor pressure of water, so the vessel is not possible at that height.
 
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