Fluid dynamics, Pipe Flow, Hagen Poiseuille, Darcy's equation

Click For Summary
SUMMARY

The discussion centers on calculating the maximum average velocity and pressure drop for laminar flow in a water injection line using the Hagen-Poiseuille equation and Darcy's equation. The specific parameters include a pipe diameter of 0.25 mm and a length of 0.75 m, leading to a maximum average velocity of 8 m/s and a pressure drop of 3,072 MPa. Participants emphasize the necessity of knowing the viscosity of water, typically around 1 centipoise at room temperature, to solve the problem accurately.

PREREQUISITES
  • Understanding of Hagen-Poiseuille equation for laminar flow
  • Familiarity with Darcy's equation for pressure drop calculations
  • Knowledge of Reynolds number and its significance in flow regimes
  • Basic principles of fluid dynamics and viscosity
NEXT STEPS
  • Research the Hagen-Poiseuille equation and its applications in fluid dynamics
  • Study Darcy's equation and its relevance to pressure drop in pipes
  • Learn how to calculate Reynolds number and its implications for flow characterization
  • Investigate the effects of temperature on the viscosity of fluids, particularly water
USEFUL FOR

Students in engineering or physics, particularly those focusing on fluid dynamics, mechanical engineers, and anyone involved in designing or analyzing piping systems.

sandpants
Messages
21
Reaction score
0

Homework Statement


A water injection line is made from smooth capillary tubing with inside
diameter D = 25.0 mm . If the length of the pipe is 0.75 m and assuming
laminar flow is present up to Re = 2000, find

(i) the maximum average velocity at which the flow is laminar
(ii) the pressure drop required to deliver this maximum velocity.

[Answer: (i) u = 8 m/s; (ii) ∆p = 3 072 MPa ]

Homework Equations


Everything related to laminar flows in pipes used the hagen poiseuille equation and Darcy's equations.

u=-1/4μ*(dP/dx)(R^2-r^2)

The Attempt at a Solution



Just some random substitutions, like setting -(dP/dx)=Δp/L and then equating that to Darcy's 4f/d*ρU^2/2

But the issue is the viscosity. I can't get rid of it, and I can't find it. Though I can understand why it is not given, as it would make things way too easy.

Anything about viscosity?
 
Physics news on Phys.org
sandpants said:

Homework Statement


A water injection line is made from smooth capillary tubing with inside
diameter D = 25.0 mm . If the length of the pipe is 0.75 m and assuming
laminar flow is present up to Re = 2000, find

(i) the maximum average velocity at which the flow is laminar
(ii) the pressure drop required to deliver this maximum velocity.

[Answer: (i) u = 8 m/s; (ii) ∆p = 3 072 MPa ]


Homework Equations


Everything related to laminar flows in pipes used the hagen poiseuille equation and Darcy's equations.

u=-1/4μ*(dP/dx)(R^2-r^2)


The Attempt at a Solution



Just some random substitutions, like setting -(dP/dx)=Δp/L and then equating that to Darcy's 4f/d*ρU^2/2

But the issue is the viscosity. I can't get rid of it, and I can't find it. Though I can understand why it is not given, as it would make things way too easy.

Anything about viscosity?

Look up the viscosity of water at room temperature. At 20C, it's about 1 centipoise.

Are you sure about that diameter? 25 mm sounds like an awfully big capillary. Did you mean 25μm?

If you know the viscosity, the density, the diameter, and the Reynolds number, you have enough info to calculate the average velocity.

The equation you wrote is not the Hagen Poiseuille equation. That equation expresses the pressure drop in terms of either the volumetric throughput rate, or equivalently, the average velocity. What is that equation?

Chet
 
Chestermiller said:
Look up the viscosity of water at room temperature. At 20C, it's about 1 centipoise.

Are you sure about that diameter? 25 mm sounds like an awfully big capillary. Did you mean 25μm?

If you know the viscosity, the density, the diameter, and the Reynolds number, you have enough info to calculate the average velocity.

The equation you wrote is not the Hagen Poiseuille equation. That equation expresses the pressure drop in terms of either the volumetric throughput rate, or equivalently, the average velocity. What is that equation?

Chet

You are right about the diameter. Its 0.25mm.

Non the less, if viscosity was given it would be awfully easy to get the velocity. Another thing is, no temperature is given, which it is a bit iffy to make an assumption about what viscosity to use. Is there no way to get it out of there?
 
sandpants said:
You are right about the diameter. Its 0.25mm.

Non the less, if viscosity was given it would be awfully easy to get the velocity. Another thing is, no temperature is given, which it is a bit iffy to make an assumption about what viscosity to use. Is there no way to get it out of there?

What's the context of this exercise? What values for the viscosity of water have you been given in your notes/textbook? In short, is there anything which suggests that you should do otherwise than assume a temperature of 20 degrees? Working backwards from the given answer suggests that you are supposed to make that assumption, so there must be something in the context to tell you that or the exercise is poorly designed.
 
  • Like
Likes   Reactions: 1 person
You know that, in the real world, you are not going to be spoon fed all the data. If you knew that the problem statement was missing the viscosity, you should have looked it up. After all, the problem statement did say room temperature. Would it have mattered much to the answer if you had used 22C or 23C? All you needed to do was to google viscosity of water. PAsmith confirmed that this would have been the right thing to do.

Chet
 
  • Like
Likes   Reactions: 1 person
I assumed that there must be a way to circumvent viscosity because the emphasis of the topic was the equation u=-1/4μ*(dP/dx)*(R^2-r^2) (for laminar flows). Knowing viscosity means you can find the velocity through reynolds number Re=ρud/μ which is kinda trivial. Only thing that's left is finding the pressure difference which is not difficult either.

All that was given was what I wrote. Something like that can pop up on the exam and I don't get to check water viscosity on the internet.

It does work out in the end, yeah. I'm asking for clarity though, is there no way to circumvent needing viscosity there?
 
Definitely not.

Chet
 

Similar threads

  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 8 ·
Replies
8
Views
19K
Replies
1
Views
4K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
9
Views
4K
Replies
5
Views
11K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K