- #1
jinman
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Homework Statement
A Partially evacuated airtight container has a tight-fitting lid of surface area 77m^2 and negligible mass. If the force required to remove the lid is 480N and the atmospheric pressure is 1x10^5 Pa, what is the air pressure inside the container?
Homework Equations
p=F/A
The Attempt at a Solution
p=F/A
p=480N/77m^2
p=6.23Pa
This did not make sense to me, so i thought maybe it was the difference in pressures:
Po-Pd=Pf
1x10^5-6.23Pa=99993.78Pa??
I don't think that is right either. Where I am going wrong?