Flux across a plane with varying electric field

AI Thread Summary
To find the electric flux through a plane at x=3 with a varying electric field E = α y^2 x i + α z^2 y j, the relevant equation is Φ = ∮ E · dA. The area element dA is directed in the i direction, leading to dA = dydz i. The flux calculation involves integrating E · dA, resulting in the expression α y^2 x dydz. After evaluating the double integral, the final result for the flux at x=3 simplifies to (L^4/3) α. The solution appears to be correct based on the provided calculations.
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Homework Statement


I got home from a test, had an extra credit problem semi memorized and am wondering how I was suppose to solve.

http://i.imgur.com/cIOdSvk.png

A plane with sides L is at x=3 . An electric field E = α y^2 x i + α z^2 y j passes through (where \alpha is a constant). Find the flux through the plane. (Givens are L, \alpha

Homework Equations



\Phi = \oint E \cdot dA

The Attempt at a Solution



Frankly I didn't feel like I knew what I was doing. The plane varies along y and z and the vector for dA will always go in the i direction

dA i = dydz i
E \cdot dA = \alpha y^2 x dydz
\int_0^L \int_0^L y^2 x dydz
L \alpha x \frac{y^3}{3}|^L_0
\frac{L^4}{3} \alpha x

x=3

L^4 \alpha
 
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Your work looks correct to me.
 
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