Flux through sphere NOT centred at origin

In summary, the conversation discusses the implementation of spherical coordinates for a sphere with a given radius and center point. The suggestion is to translate the origin in order to obtain the formula for the surface area of the sphere. The help is greatly appreciated but the solution is still being sought after.
  • #1
sandy.bridge
798
1

Homework Statement


Let's say the sphere has a radius of 3 and is centred at (3, 0, 3). Is there a way to implement spherical cooridnates, or is it essentially impossible for this situation to not get messy? I have searched everywhere as to how I can evaluate this, but to no avail. Any help is greatly appreciated.
 
Physics news on Phys.org
  • #2
sandy.bridge said:

Homework Statement


Let's say the sphere has a radius of 3 and is centred at (3, 0, 3). Is there a way to implement spherical cooridnates, or is it essentially impossible for this situation to not get messy? I have searched everywhere as to how I can evaluate this, but to no avail. Any help is greatly appreciated.

Try translating the origin. If the sphere is centered at (a,b,c) try$$
x = a+\rho \sin \phi \cos\theta$$ $$
y = b +\rho \sin \phi \cos\theta$$ $$
z = c +\rho\cos\phi$$This will give you the usual formua for ##d\vec S##. ##\rho## would be the constant radius of the sphere.
 

1. What is flux through a sphere not centered at the origin?

The flux through a sphere not centered at the origin is the measure of the flow of a vector field through the surface of the sphere. It takes into account the distance of the sphere from the origin, as well as the direction and magnitude of the vector field at each point on the surface of the sphere.

2. How is the flux through a sphere not centered at the origin calculated?

The flux through a sphere not centered at the origin is calculated using the surface integral formula: Φ = ∫∫S F · dS, where Φ is the flux, F is the vector field, and dS is the differential surface element. This formula takes into account the vector field and the orientation of the surface.

3. What factors affect the flux through a sphere not centered at the origin?

The flux through a sphere not centered at the origin is affected by the distance of the sphere from the origin, the direction and magnitude of the vector field, and the orientation of the surface. It is also affected by the shape and size of the sphere, as well as any obstacles or boundaries within the vector field.

4. How does the direction of the vector field affect the flux through a sphere not centered at the origin?

The direction of the vector field at each point on the surface of the sphere affects the flux by determining whether the vector field is flowing into or out of the sphere. If the vector field is flowing in the same direction as the normal vector of the surface, the flux will be positive. If the vector field is flowing in the opposite direction, the flux will be negative.

5. Can the flux through a sphere not centered at the origin be negative?

Yes, the flux through a sphere not centered at the origin can be negative. This occurs when the vector field is flowing in the opposite direction of the normal vector of the surface. In this case, the flux is considered to be entering the surface instead of exiting it, resulting in a negative value.

Similar threads

  • Calculus and Beyond Homework Help
Replies
5
Views
784
  • Calculus and Beyond Homework Help
Replies
1
Views
956
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
  • Calculus and Beyond Homework Help
Replies
4
Views
1K
  • Calculus and Beyond Homework Help
Replies
6
Views
2K
  • Calculus and Beyond Homework Help
Replies
9
Views
8K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Calculus and Beyond Homework Help
Replies
15
Views
2K
Replies
5
Views
1K
Back
Top