Flux through sphere NOT centred at origin

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SUMMARY

The discussion focuses on evaluating the flux through a sphere with a radius of 3, centered at the coordinates (3, 0, 3). The key solution involves translating the origin to simplify the implementation of spherical coordinates. By using the transformation equations: x = a + ρ sin φ cos θ, y = b + ρ sin φ sin θ, and z = c + ρ cos φ, where ρ represents the constant radius, the problem can be effectively addressed without excessive complexity.

PREREQUISITES
  • Understanding of spherical coordinates and their transformations
  • Familiarity with vector calculus and flux concepts
  • Knowledge of coordinate translation techniques
  • Basic proficiency in mathematical notation and symbols
NEXT STEPS
  • Study the derivation of spherical coordinates in non-origin-centered systems
  • Learn about vector field flux calculations using the Divergence Theorem
  • Explore advanced applications of coordinate transformations in multivariable calculus
  • Investigate the implications of translating coordinates in physics problems
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Students and educators in mathematics, particularly those studying multivariable calculus, as well as physicists dealing with flux evaluations in non-standard coordinate systems.

sandy.bridge
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Homework Statement


Let's say the sphere has a radius of 3 and is centred at (3, 0, 3). Is there a way to implement spherical cooridnates, or is it essentially impossible for this situation to not get messy? I have searched everywhere as to how I can evaluate this, but to no avail. Any help is greatly appreciated.
 
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sandy.bridge said:

Homework Statement


Let's say the sphere has a radius of 3 and is centred at (3, 0, 3). Is there a way to implement spherical cooridnates, or is it essentially impossible for this situation to not get messy? I have searched everywhere as to how I can evaluate this, but to no avail. Any help is greatly appreciated.

Try translating the origin. If the sphere is centered at (a,b,c) try$$
x = a+\rho \sin \phi \cos\theta$$ $$
y = b +\rho \sin \phi \cos\theta$$ $$
z = c +\rho\cos\phi$$This will give you the usual formua for ##d\vec S##. ##\rho## would be the constant radius of the sphere.
 

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