Flywheel and Gearbox Coupling Help

AI Thread Summary
The discussion revolves around calculating the holding torque required for a gearbox and flywheel system. The gearbox has an efficiency of 92%, with the output shaft rotating in the opposite direction at five times the speed of the input shaft. The user successfully calculated the angular velocities, angular acceleration, and moment of inertia for the solid flywheel. They initially struggled with determining the holding torque but received guidance on using input power and angular velocity to find the solution. Ultimately, the user confirmed their understanding and resolved the problem.
Mingsliced
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Homework Statement


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I've been working my way through the following question but I am a little bit stuck at this part:

A gearbox and flywheel are as shown in FIGURE 4. The output shaft rotates in the opposite direction to the input shaft at 5 times its speed. The gearbox has an efficiency of 92%.

If the flywheel is solid, has a mass of 50 kg, a diameter of 1.5 m and is to accelerate from rest to 300 revs min–1 in 1 minute:

Calculate the magnitude and direction of the torque required to hold the gearbox stationary (holding torque Th).

Homework Equations


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Input shaft rotating clockwise.
Output shaft rotating anti-clockwise.

Input Angular Velocity W1 = 0 RAD/s
Final Angular Velocity W2 = (300*2π)/60
Final Angular Velocity W2 = 31.42 RAD/s

Angular Acceleration α = (W2 - W1)/t
Angular Acceleration α = (31.42 - 0)/60
Angular Acceleration α = 0.52 RAD/s

Moment of inertia for solid disc I = 1/2*MR2
Moment of inertia for solid disc I = 0.5*50*0.752
Moment of inertia for solid disc I = 14.06 KG/m2

Torque of output shaft T2 = I*α
Torque of output shaft T2 = 14.06*0.52
Torque of output shaft T2 = 7.3Nm
Regarding gearbox efficiency T2 = (7.3/100)*92
Therefore T2 = 6.716Nm

Torque of input shaft T1 = T2 * 5
Torque of input shaft T1 = 6.716 * 5
Torque of input shaft T1 = 33.58Nm

The Attempt at a Solution



I'm struggling because a lot of the worked examples already have input or output power, which is what I need to calculate the holding torque TH. Could I calculate the output power using T2 * W2? Thus 6.716 * 31.42 = 211Kw and work backwards from there?

Cheers!
 
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I haven't checked your arithmetic but you seem to be doing ok so far.

Take a look at your worked examples again. How do they get from input power to holding torque?
 
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By using the angular velocity Wi: input power = Ti * Wi.

I'm guessing to get Wi that you divide the output speed by 5, so 300/5 = 60. Then convert to RAD/s to get 6.283 RAD/s.

Then placing that into input power formula: 33.58 * 6.283 = 210.98 Watts.

Is that correct?
 
Don't worry, I've figured it out. The above post is incorrect anyway. Thanks for the hint :)
 
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