- #1
Bryon
- 98
- 0
Hey everyone! I have a small problem with part b. I am wondering if i miscalculated something. Any ideas? Thanks!
A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 4.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.
--------------------------------------------------------------------------------
a) When the 4.7 kg weight is dropping with a speed of 1.1 m/s, what is the angular velocity of the flywheel?
w = rad/s *
4.4 OK
--------------------------------------------------------------------------------
b) When the 4.7 kg weight is moving with a speed of 1.1 m/s, what is the kinetic energy of the entire system? This one seems really easy, but for some reason I keep getting the wrong answer.
K(rotational) = 0.5Iw^2
I = 0.5m(wheel)r^2
KE = 0.5m(block)v^2
KE(system) = 0.5[0.5m(wheel)r^2]w^2 + 0.5m(block)v^2
0.5*[0.5*15*0.25^2]*(4.4^2) + 0.5*4.7*(1.1^2)
KE(system) = 4.5375 + 2.8435 = 7.381 J
For some reason 7.381 is not correct.
Homework Statement
A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 4.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.
--------------------------------------------------------------------------------
a) When the 4.7 kg weight is dropping with a speed of 1.1 m/s, what is the angular velocity of the flywheel?
w = rad/s *
4.4 OK
--------------------------------------------------------------------------------
b) When the 4.7 kg weight is moving with a speed of 1.1 m/s, what is the kinetic energy of the entire system? This one seems really easy, but for some reason I keep getting the wrong answer.
Homework Equations
K(rotational) = 0.5Iw^2
I = 0.5m(wheel)r^2
KE = 0.5m(block)v^2
The Attempt at a Solution
KE(system) = 0.5[0.5m(wheel)r^2]w^2 + 0.5m(block)v^2
0.5*[0.5*15*0.25^2]*(4.4^2) + 0.5*4.7*(1.1^2)
KE(system) = 4.5375 + 2.8435 = 7.381 J
For some reason 7.381 is not correct.
Last edited:
