Flywheels and Rotational Motion

AI Thread Summary
A low-pollution automobile concept utilizes a 240 kg flywheel to store energy, enabling a 300 km travel distance without a spinup. The discussion emphasizes calculating the total energy required, estimated at approximately 1.6 x 10^8 J, by considering frictional forces and energy conservation principles. Concerns about safety arise, particularly regarding the potential dangers of a flywheel detaching during an accident, which could lead to significant damage. Additionally, the necessity of spinups for varying elevations and energy storage limits is highlighted. Overall, the feasibility and safety of flywheel energy storage in vehicles remain key considerations.
Soaring Crane
Messages
461
Reaction score
0
One possibility for a low-pollution automobile is for it to use energy stored in a heavy rotating flywheel of mass 240 kg, and should be able to travel 300 km (300,000 m) without needing a flywheel "spinup."

Make reasonable assumptions (avg. frictional retarding force 500 N, 20 acceleration periods from rest to 90 km/h or 25 m/s, equal uphill and downhill --assuming during downhill, energy can be put back into the flywheel), and show that the total energy needed to be stored in fly wheel is about 1.6 x 10^8 J.


I need help to start this proof. Do you use K_i + U_i = K_f + U_f? What do I do from here?

Thanks for any pointers.
 
Last edited:
Physics news on Phys.org
try using K_rotatational also
k_rot = (1/2)IW^2 --> I is inertia, W is omega (angular speed)
 
What happens to the energy stored in the flywheel if you should be come involved in an accident? I have visions of a massive flywheel with a large rotational kinetic energy busting loose from its housing and ripping off down the road destroying car after car, each of which releases a flywheel! Talk about a chain reaction accident!

Yeah, I know that is a bit extreme, but containment is an issue.

Also spinups will be necessary. Suppose I drive from my home at 100m to spend a week in the mountains at 1000m? A spinup may well be necessary to meet my needs for a week. Now on the way home, I may find myself with more energy to store then the flywheel is designed for.

Just some thoughts, the fact is, for years I have speculated about using a flywheel for automotive energy storage.
 
Now to address your question!

According to your assumptions the only loss will be that due to friction. If you simply compute the work done by your friction force over 300km, you should have your answer.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top