Fnet = 45.0Find Accel. in Airport Problem with 24.0 kg & 45.0 N Force

  • Thread starter Thread starter Kdawg
  • Start date Start date
AI Thread Summary
To find the acceleration of the 24.0 kg object being pulled at an angle with a 45.0 N force, the net force in the horizontal direction (Fx) is calculated as 41.72 N, and the vertical force (Fy) is 18.86 N. Since friction is negligible, the acceleration can be determined using Newton's second law, F=ma. The total net force acting on the object is the horizontal component, which leads to the calculation of acceleration. The discussion highlights the importance of recognizing the relationship between force and acceleration in solving the problem.
Kdawg
Messages
34
Reaction score
0
A woman at an airport is pulling her 24.0 kg by a strap at an angle of 22 ° above the horizontal as shown in figure Fig. P5.44. She pulls on the strap with a 45.0 N force, and friction is negligible.
How would you find acceleration in this problem, there doesn't seem to be enough info but I know there is.
I calculated this
Fx = 41.72
Fy = 18.86
 
Physics news on Phys.org
Well... how do you relate force and acceleration...
 
lol, duh F=ma
 
thank you, I just needed that little hint
 
anytime :approve:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top