Fnet = 45.0Find Accel. in Airport Problem with 24.0 kg & 45.0 N Force

  • Thread starter Thread starter Kdawg
  • Start date Start date
AI Thread Summary
To find the acceleration of the 24.0 kg object being pulled at an angle with a 45.0 N force, the net force in the horizontal direction (Fx) is calculated as 41.72 N, and the vertical force (Fy) is 18.86 N. Since friction is negligible, the acceleration can be determined using Newton's second law, F=ma. The total net force acting on the object is the horizontal component, which leads to the calculation of acceleration. The discussion highlights the importance of recognizing the relationship between force and acceleration in solving the problem.
Kdawg
Messages
34
Reaction score
0
A woman at an airport is pulling her 24.0 kg by a strap at an angle of 22 ° above the horizontal as shown in figure Fig. P5.44. She pulls on the strap with a 45.0 N force, and friction is negligible.
How would you find acceleration in this problem, there doesn't seem to be enough info but I know there is.
I calculated this
Fx = 41.72
Fy = 18.86
 
Physics news on Phys.org
Well... how do you relate force and acceleration...
 
lol, duh F=ma
 
thank you, I just needed that little hint
 
anytime :approve:
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top