Football player kinematics in one dimension

AI Thread Summary
A football player accelerates from rest for 3 seconds before changing his acceleration to 1.1 m/s² for an additional 2 seconds, reaching a final speed of 6.4 m/s. The discussion focuses on determining the player's initial acceleration during the first 3 seconds. Participants suggest using kinematic equations to relate time, velocity, and acceleration. The correct approach involves calculating the velocity at the 3-second mark using the known final velocity and acceleration. The final calculated acceleration for the initial period is confirmed to be 1.4 m/s².
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Homework Statement



A football player, starting from rest at the line of scrimmage, accelerates along a straight line for a time of 3 seconds. Then during a negligible amount of time, he changes the magnitude of his acceleration to a value of 1.1 m/secondssquared. With this acceleration, he continues in the same direction for another 2 seconds until he reaches a speed of 6.4 m/sec. What's the value of his acceleration (assumed to be constant) during the initial 3 sec period?

Homework Equations



kinematics

The Attempt at a Solution



I tried drawing a graph but to no avail. How would I do it with just equations?
 
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You'll have to pick out an equation to use first. As you are given times, velocities and accelerations - something relating the three of those could be handy. Can you find one?
 
v=vinital+at
but i don't understand what 1.1 m/s sqrd is for...is that the acceleration during the 3sec-5sec time period? i don't know what to plug in
 
Good equation choice and yes, that's what the 1.1m/sec^2 is. So first concentrate on the 3-5 sec period. You know the final velocity (at 5 sec) and you know the acceleration. Can you determine the velocity at 3 sec? BTW write the equation as v=vinitial+a*(t-tinitial) where tinitial is 3 sec for this time period.
 
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Ok, so I got that stuff plugged in but the acceleration isn't there...what would that be?
 
Ohhh ok, so 1.1 is the magnitude of the acceleration so that means it IS the acceleration from 3-5 seconds right?
 
Right. You may find it easier to work with your equation in the form (change of v)=a*(change of t).
 
Ok, so i got 1.4 m/s^2 but i don't know if that's the right answer? can anyone do it and see what they get/help me? =)
 
Yes, that's right.
 
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Yay, thank you so much for your help =)
 
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