Force acting on wedge and block

AI Thread Summary
To maintain the box at a constant height above the table when a wedge is pushed by a constant force, the force must counteract the gravitational component acting on the box. This gravitational force is calculated as (mg)/(sin alpha), where m is the mass of the box and alpha is the angle of the wedge. The force exerted on the wedge must equal this gravitational force to prevent any vertical movement of the box. The discussion highlights the challenge of identifying the source and direction of the force acting on the block. Understanding these forces is crucial for solving the problem effectively.
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http://i257.photobucket.com/albums/hh216/Megatallica/wedge.jpg


When the wedge is pushed by the constant force, how big must the force be in magnitude to keep the box at a constant height above the table. Assume no friction.

Well the force pulling the box down is a component of its gravity right? So this force is equal to (mg)/(sin alpha). A force, caused by the force accelerating the wedge must cancel this force out right? But I am having trouble identifying where it is coming from and what way it is acting on the block...
 
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