Force applied to lawnmower and resulting acceleration

Thread starter NewJersey
Start date Nov 16, 2007
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Acceleration Applied Force Force applied

AI Thread Summary

The discussion focuses on calculating the acceleration and upward force exerted by a lawnmower being pushed with a force of 30N at a 37-degree angle downward. The calculations yield an acceleration of approximately 0.96 m/s² and a total upward force of 263N, considering the weight of the lawnmower and the vertical component of the applied force. There is a question regarding the gravitational constant used, with a suggestion that 9.87 m/s² might be a typo, as the standard value is typically 9.81 m/s². The calculations appear to be generally correct, but clarification on the gravitational constant is needed. Overall, the thread addresses the physics of force and acceleration in the context of a lawnmower's movement.

Nov 16, 2007

NewJersey

A 25-kg lawnmover is pushed with a force of 3oN directed 37degrees downward fron the horizontal?

a) The acceleration of the lawnmover is
b) The upward force exerted by the lawn is

Fx= 30 cos(37)= 23.96N
Fy= 30 sin(37)= 18N

a= 23.96N
25kg = .96m/s^2

b= W=25* 9.87= 245

W+Fy= 245+18= 263

Is this right?

Homework Equations

The Attempt at a Solution

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Nov 17, 2007

einstein_a_go_go

looks OK to me (is g=9.87 a typo?)

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