Force, Electric Field, and Positive Particle

In summary, the question asks for the location of points where an alpha particle would experience no force in a setup where a line with a uniform charge density of 50.0 microcoulombs/m is placed parallel to a large, flat plastic sheet with a uniform surface charge density of -100 microcoulombs/m^2 on one side. Using the equations E = [1/(2*episilon_0*pi)]*(lambda/r) for the wire and E = omega/(2*episilon_0) for the sheet, the attempt at a solution finds that the distance from the line at which the alpha particle would feel no force is 0.1592 m, which would be above the line. This is
  • #1
Soaring Crane
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0

Homework Statement



A long line carrying a uniform linear charge density 50.0 microcoulombs/m runs parallel to and 10.0 cm from the surface of a large, flat plastic sheet that has a uniform surface charge density of -100 microcoulombs/m^2 on one side.

Find the location of all points where an alpha particle would feel no force due to this arrangement of charged objects.
Indicate this location as a distance from the line.

Choose an appropriate location of these points at a distance: above the line or between the line and the sheet.

Homework Equations



E = [1/(2*episilon_0*pi)]*(lambda/r) for wire

E = omega/(2*episilon_0) for sheet (Do I use this formula?)


The Attempt at a Solution



I don’t know if I set this up correctly or used the correct formulas.

E = [1/(2*episilon_0*pi)]*(lambda/r) + omega/(2*episilon_0)

0 = [1/(2*episilon_0*pi)]*(lambda/r) + omega/(2*episilon_0)

-omega/(2*episilon_0) = [1/(2*episilon_0*pi)]*(lambda/r)

r = (lambda)/(-omega*pi) = (50*10^-6 C/m)/[pi -(-100*10^-6 C/m^2)] = 0.1592 m ?

This distance would be above the line because the electric field vectors, which are in same direction as force vectors, on the positive alpha particle would be in opposite directions??

Thanks.
 
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  • #2
It looks fine to me. Is something unclear?
 
  • #3


I would first like to commend you on your attempt at solving this problem. Your equations and approach are correct, and you have correctly identified the distance above the line as the location where an alpha particle would experience no force.

To further explain, the electric field due to the line and the sheet can be calculated separately using the equations you provided. The electric field due to the line will be directed away from the line, while the electric field due to the sheet will be directed towards the sheet. At the location where the two electric fields cancel out, the net electric field will be zero and the alpha particle will experience no force.

This location will be above the line because, as you correctly stated, the electric field and force vectors for a positive particle are in opposite directions. Therefore, the electric field due to the line must be greater than the electric field due to the sheet in order for them to cancel out. This is why the distance must be above the line, as the electric field due to the sheet will always be directed towards the sheet.

Overall, your solution and understanding of the problem are correct. Keep up the good work!
 

What is force?

Force is a physical quantity that describes the push or pull on an object. It is measured in Newtons (N) and can be represented by a vector with both magnitude and direction.

What is an electric field?

An electric field is a region of space where an electrically charged particle experiences a force. It is created by other charged particles and is defined as the force per unit charge at a given point in space.

How does force affect a positive particle in an electric field?

A positive particle in an electric field will experience a force in the direction of the electric field if it is moving in the same direction as the field. If the particle is moving against the direction of the field, it will experience a force in the opposite direction.

What is the relationship between force and electric field?

The force on a charged particle in an electric field is directly proportional to the electric field strength and the charge of the particle. This relationship is described by the equation F = qE, where F is the force, q is the charge, and E is the electric field strength.

How are positive particles affected by electric fields in different materials?

The effect of an electric field on a positive particle depends on the material it is in. In conductors, the electric field induces movement of charges, creating an opposing field. In insulators, the electric field cannot induce movement of charges, so the particle will experience a constant force in the same direction as the field.

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