Force in kinetic energy/force in momentum =1

AI Thread Summary
The discussion centers on demonstrating that the force calculated from kinetic energy and momentum is equivalent using given parameters. The kinetic energy is calculated as 1000 lb(ft/sec)², while momentum is determined to be 200 lb(ft/sec). Both methods yield a force of 100 lb, confirming their equivalence. However, there is a concern regarding unit consistency, particularly the need to account for mass and gravitational acceleration. The final question seeks confirmation on whether the calculated force of 100 lb is correct.
morrobay
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Homework Statement


mass=20
V1=0
V2=10ft/sec
t=2 sec
a=5'/sec/sec
x=10ft
I want to show that the force in momentum and in kinetic energy from above data is the same. With the understanding that simple algebra is being superimposed on calculus.


Homework Equations


K.E.= integral of force over distance= max=mdv/dt (dx) =1/2mv^2
momentum = integral of force over time = mv
force= K.E./change in distance
force=momentum/change in time



The Attempt at a Solution


K.E.= 1000 lb (ft/sec)^2
momentum=200 lb(ft/sec)
The force from kinetic energy = 1000 lb (ft/sec)^2 /10ft =100 lb
The force from momentum = 200 lb (ft/sec)/2 sec= 100 lb
Same force, correct ?


 
Last edited:
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I am not sure how your units work, but lbs is a force, so you'd need to divide by acceleration due to gravity to get the mass.
 
rock.freak667 said:
I am not sure how your units work, but lbs is a force, so you'd need to divide by acceleration due to gravity to get the mass.

OK the mass =20 by correction.
Now is the 100 lb force correct ?
 
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