Force Law for 2D Motion with Const a,b,w: F = F(r)

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A body of mass m moves in two dimensions under a force F, following the trajectory r(t) = aCos(wt)x^ + bSin(wt)y^. The constants a, b, and w define the motion, which describes an elliptical path that is not governed by Kepler's laws. To derive the force law F = F(r), one applies Newton's second law, expressed as F = m(d²r/dt²). The discussion highlights the confusion around applying this law to the specific trajectory and emphasizes the need to understand the relationship between acceleration and the trajectory's parameters. Clarifying these concepts is essential for grasping the underlying physics of the motion described.
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A body of mass m moves under the influence of a force F in two dimensions. It has an trajectory
r(t) = aCos(wt)x^ + bSin(wt)y^

a = alpha
b = beta
w = omega, they are not a, b, and w in alphabet
x^,y^: vector unit

a,b,w are constant. Find the force law F = F(r) which corresponds to this motion (This trajectory is an ellipse, but not Keplerian ellipse. Newton's Law of Gravitaion is not the force law you seek here).
 
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Hint: Newton's second law of motion.
 
Can you explain more in detail, it still confuses me. How do we derive the fomular of Newton's Second Law F=ma to this kind of fomular:confused:
 
Well we have;

\vec{F} = m\vec{a}
\vec{F} = m\frac{d\vec{v}}{dt}
\vec{F} = m\frac{d^2\vec{r}}{dt^2}

Can you go from here?
 
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I have to admit that I'm stupid, I know the Newton's Second Law. But how to get to r(t) = aCos(wt)x^ + bSin(wt)y^
 
What does m\frac{d^2\vec{r}}{dt^2} mean to you?
 
My god man! I've forgot my d's! Duly corrected ...
 
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