Force on Series of Springs: Does It Equal Sum?

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When two springs with different spring constants are arranged in series, the force applied to each spring is the same, represented by F = k1Δl1 for the first spring and F = k2Δl2 for the second. The total force is not equal to the sum of the spring constants multiplied by the total distance stretched. Instead, the equivalent spring constant for springs in series is calculated using the formula 1/k = 1/k1 + 1/k2. This means that the overall behavior of the system is governed by the individual spring constants rather than their sum. Understanding this relationship is crucial for accurately analyzing spring systems in physics.
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If two springs, having different spring constants, are in a series (lined up, NOT parrallel): is the Force pulling the spring = (sum of spring constants)*(distance stretched) ?
 
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No, no. If the force apply to the 1^{st} spring, the equation will be

F=k_1\Delta l_1[/color]
 
so the same force is applied to both springs?
 
in other words, if F = kx:
F=(k1)(x1)
and
F=(k2)(x2)

but not F=(k1+k2)(x1+x2)
 
That's right, and the equivalent constant is

\frac{1}{k}=\frac{1}{k_1}+\frac{1}{k_2}+...+\frac{1}{k_n}[/color]
 
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