Force on the top screw in a hanging basket scenario

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AI Thread Summary
The discussion centers on the forces acting on the top screw in a hanging basket scenario, with two differing opinions on whether the force changes based on the design orientation. One participant argues that the top screw experiences more force in certain tie scenarios, while the other contends that the force remains constant regardless of orientation. They agree that using the lower screw as a pivot point helps analyze the moments and forces involved. The conversation emphasizes the need for exact mathematical equations to resolve their disagreement. Ultimately, they seek clarity on the torque calculations to determine the forces acting on the screws accurately.
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Homework Statement



Hi and Thanks to anyone that takes time to help!

This is not a homework thing but a 'discussion' with friends.
Please excuse my crappy drawings...
5lcojk.jpg


The measurments are not important only that it is the same frame either with strut or reversed for tie.

The difference in opinion is simply that one says there is more force pulling the top screw from the wall in the tie senarios of each design, while the other says there is no difference in force on the top screw either way round.

(We are both in our late 30's so it was some time since working out any actual equations- let alone remembering which ones are relevant)

Homework Equations



Errr...vectors, moments..??

The Attempt at a Solution



It's been too long but only exact maths is going to conclude this little discussion!

Please, please can you prove the error in one of our heads and make the other safe in the knowledge they are not a complete idiot!

EDIT:Have I put this in teh wrong section? It just seemed the best place fer an exact answer.
 
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Basketcase said:
The difference in opinion is simply that one says there is more force pulling the top screw from the wall in the tie senarios of each design, while the other says there is no difference in force on the top screw either way round.
If we assume the lower screw as the pivot, then the moment around it and the pull on the upper screw are the same in each case.
 
A.T. said:
If we assume the lower screw as the pivot, then the moment around it and the pull on the upper screw are the same in each case.

Thanks A.T.,

Would the pivot not be the bottom end of the bar against the wall and does that make any difference?

What equations need to be used to work out exact numbers for the force acting on the top screw in both senarios for each design?
 
Basketcase said:
Would the pivot not be the bottom end of the bar against the wall
That might be more sensible. Then both screws are pulled.
Basketcase said:
and does that make any difference?
Not between the designs, if the distance of the screws to the bottom end of the bar is the same for all of them
Basketcase said:
What equations need to be used to work out exact numbers for the force acting on the top screw in both senarios for each design?
http://en.wikipedia.org/wiki/Torque
You compute the torque created by the given force (M = F1 * r1) and then you use this torque to compute the pull force on the screw (F2 = M / r2). Where r is the shortest distance between the pivot and the line of action of F.
 
Thanks again A.T., I just need to try to work it out when I have time and will maybe show my workings here for probable corrections!
 
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