How Is Force Calculated on a Plate Stopping Water in a Pipe?

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To calculate the force exerted on a plate that stops water flowing at 7 m/s in a pipe with a radius of 5 cm, consider the pressure wave propagation at the speed of sound in water, which is 1.4 km/s. The mass of water brought to a stop can be determined using the volume of water in a length of tube equal to the speed of sound multiplied by the time interval and the cross-sectional area of the pipe. The force can then be calculated using the formula P = F/A, where A is the cross-sectional area. The force is derived from the time rate of change of momentum of the stopped water. Understanding these principles allows for the accurate calculation of the force on the plate.
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Homework Statement



Water flows at 7 m/s in a pipe of radius 5 cm. A plate having an area equal to the cross-sectional area of the pipe is suddenly inserted to stop the flow. Find the force exerted on the plate. Take the speed of sound in water to be 1.4 km/s. (Hint: When the plate is inserted, a pressure wave propagates through the water at the speed of sound vs. The mass of water brought to a stop in time Δt is the water in a length of tube equal to vsΔt.)

Homework Equations



P = F/A

The Attempt at a Solution



I am trying to attempt the problem in the following way: Consider a reference frame where the water is still. Then the insertion of the plate would actually be a plate moving at 7 m/s, causing the still water to start moving. However, I am not sure how to get the force from this. It's probably going to be from P = F/A. Can anyone help me get started on this problem?
 
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You can easily work it out using the hint. The amount of water stopped by the plate is v*dt*A where A=pi*r*r. Now you can find mass and momentum stopped using density and initial velocity of flowing water. Force is thus time rate of change of momentum. Since I can not think of a retarding force on water other than that by the plate, this may be the answer.
 
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