Force provided during deceleration?

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SUMMARY

The discussion centers on calculating the force exerted by rockets on a spacecraft with a mass of 9100 kg, initially traveling at 8 m/s and decelerating to 0.03 m/s over 10 seconds while burning 100 kg of fuel. The key equations used include acceleration (∆v/t) and force (F = m x a). The calculated acceleration is 7.97 m/s², leading to a force of approximately 7,252.7 N. The complexity arises from the variable mass of the spacecraft due to fuel consumption during deceleration.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m x a)
  • Knowledge of kinematic equations for acceleration
  • Familiarity with variable mass systems in physics
  • Basic principles of momentum (F x t = m x v)
NEXT STEPS
  • Study variable mass systems in classical mechanics
  • Learn about the conservation of momentum in rocket propulsion
  • Explore advanced kinematic equations for changing mass
  • Investigate real-world applications of rocket force calculations
USEFUL FOR

Students in physics, aerospace engineers, and anyone interested in understanding the dynamics of spacecraft propulsion and deceleration.

TommyChestnut
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Homework Statement


A spacecraft with a mass of 9100kg (incl fuel) traveling at 8 m/s
Rockets fire for 10 seconds burning 100kg of fuel slowing the spacecraft to 0.03 m/s
What is the force the rockets provided during the 10 seconds?

Homework Equations


acceleration = ∆v/t
F = m x a[/B]

The Attempt at a Solution


a = 8m/s - 0.03m/s = 7.97m/s
F = 9100kg x 7.97ms / 10s
F = 7.252.7

I just wanted to check the equations I have used for this problem are correct as I am getting confused with changes in momentum F x t = m x v[/B]
 
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TommyChestnut said:

Homework Statement


A spacecraft with a mass of 9100kg (incl fuel) traveling at 8 m/s
Rockets fire for 10 seconds burning 100kg of fuel slowing the spacecraft to 0.03 m/s
What is the force the rockets provided during the 10 seconds?

Homework Equations


acceleration = ∆v/t
F = m x a[/B]

The Attempt at a Solution


a = 8m/s - 0.03m/s = 7.97m/s
F = 9100kg x 7.97ms / 10s
F = 7.252.7

I just wanted to check the equations I have used for this problem are correct as I am getting confused with changes in momentum F x t = m x v[/B]
You have a variable mass situation here, since you are burning fuel to slow the spacecraft .
 

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