Force (Thrust) produced by a water pump at hose end

AI Thread Summary
To calculate the thrust produced by a water pump at the end of a hose, the key parameters include the flow rate, hose diameter, and pump head. The thrust can be determined using the formula F = ρ * Q * v, where ρ is the fluid density, Q is the flow rate, and v is the exit velocity of the water. Given the specifications, the velocity can be derived from the flow rate and hose area. The discussion aims to ascertain if the pump can generate enough thrust to lift a 10kg weight, requiring approximately 98N of force. Further calculations and clarifications on parameters may be needed for precise results.
als29192
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Hi all,

I have been searching for days (and trying many different formulas) to try and work out the force (thrust) produced by a water pump at the end of a hose (given a perfect frictionless world) and was hoping someone could help...

The following specifications are given:

Fluid: Water (Density = 1000kg/m3)
Inlet/Outlet/Hose diameter: 6cm
Inlet/Outlet/Hose area: 0.028m2
Flow rate of pump: 1000L/m
Pump Head: 25m = 3.5kg/cm2 - Head to Pressure: p(kg/cm2) = 0.1 h(m)
Starting velocity of water: 0m/s
Pump height: 0m

What would be the correct formula to determine the thrust produced by the exiting water, think of the hose exit as a rocket engine exit... Essentially, I'm trying to workout if the following theoretical pump could lift say a 10kg weight off the ground (require around 98N for force).

If you need any more information please let me know!

Thanks,

Adam
 
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