You drag a suitcase of mass 17 kg with a
force of F at an angle 40.6◦ with respect to
the horizontal along a surface with kinetic
coefficient of friction 0.59.
The acceleration of gravity is 9.8 m/s2 .
If the suitcase is moving with constant ve-
locity 2.68 m/s, what is F?
Answer in units of N.
Ff = miuFn
All forces equal
The Attempt at a Solution
so first i broke it into components,
Ff = Fcostheta
Fn + Fsin theta = Fg
Ff = miuFn = miu( Fg - Fsin theta)
miu ( Fg - Fsin theta) = Fcos theta
i got up to here and idk how to solve it