Forces Acting on a Moving Hinged Bar

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The discussion revolves around calculating the velocity of a weight at the end of a hinged bar when released from an angle. The user initially attempts to determine the resultant forces and acceleration using basic physics formulas but encounters issues with the bar changing length during motion. A suggestion is made to apply the conservation of energy principle, where potential energy (PE) converts to kinetic energy (KE) as the weight falls, providing a more accurate model. The conversation also touches on how to calculate the x and y components of velocity using trigonometric relationships based on the motion's circular path. The user expresses interest in applying these principles to a personal project inspired by a game.
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Hi all,

Okay, so the problem. Say we have a bar fixed to a horizontal surface by a hinge, at the end of the bar is a weight, which is fixed so that it cannot move. The bar is lifted to some angle \theta and let go of. I'm ignoring air resistance and the weight of the bar.

I'm trying to calculate the velocity of the weight at the end of the bar by finding the resultant force on it and then using a = F/m, then v = u + at.
This is all happening in something I've programmed, so at set intervals I'll be recalculating the forces acting, then the acceleration and hence the velocity. The weight is then moved by the velocity (x and y components) and I draw a line from the weight to the hinge to indicate the bar.
I've said that the weight has weight W. Parallel to the slope the component of the weight is W*sin(\theta) will cancel with the compression of the bar pushing back up (as these will be equal, assuming the bar does not change length).
This leaves W*cos(\theta), the perpendicular component of W, as the force moving the system.

I then say that, in x and y components, this comes out to be:
Fx = W*cos(\theta)*sin(\theta)
Fy = W*cos2(\theta)This almost works: the motion is in the correct direction and looks great for some situations. However, the bar ends up changing length - and quite substantially in some situations.

So, what have I done wrong? What are the actual x and y components of the force moving the system?

Thanks in advance for any help!
 
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Ninjakannon said:
Hi all,

Okay, so the problem. Say we have a bar fixed to a horizontal surface by a hinge, at the end of the bar is a weight, which is fixed so that it cannot move. The bar is lifted to some angle \theta and let go of. I'm ignoring air resistance and the weight of the bar.

I'm trying to calculate the velocity of the weight at the end of the bar by finding the resultant force on it and then using a = F/m, then v = u + at.
This is all happening in something I've programmed, so at set intervals I'll be recalculating the forces acting, then the acceleration and hence the velocity. The weight is then moved by the velocity (x and y components) and I draw a line from the weight to the hinge to indicate the bar.



I've said that the weight has weight W. Parallel to the slope the component of the weight is W*sin(\theta) will cancel with the compression of the bar pushing back up (as these will be equal, assuming the bar does not change length).
This leaves W*cos(\theta), the perpendicular component of W, as the force moving the system.

I then say that, in x and y components, this comes out to be:
Fx = W*cos(\theta)*sin(\theta)
Fy = W*cos2(\theta)


This almost works: the motion is in the correct direction and looks great for some situations. However, the bar ends up changing length - and quite substantially in some situations.

So, what have I done wrong? What are the actual x and y components of the force moving the system?

Thanks in advance for any help!

An easier way to do this would be to use the fact that KE + PE = Total Energy is a constant for this system. So if the weight started out at some height with no velocity before being dropped, that would give it a starting PE (do you know how to calculate that?). Then as it falls through its arc, it gives up PE and gains KE. The velocity is always along the arc, so that KE translates into horizontal and vertical velocity vector components.

Maybe try it from this perspective, and see if you get a more natural-looking fall.

BTW, this looks to be a work or personal project, or maybe upper division programming/simulation work. If it's simple homework, I should move this to the Homework Help forums. Can you say what this is for?
 
Thanks for the reply, berkeman.

This is for a personal project. I'm actually trying to get some fundamentals down before I attempt to create some frameworks; I played World of Goo recently and wondered whether I could produce some similar, although simpler, structures.Thinking about it, would your energy method also work for larger structures? I imagine so, at a glance.

The potential energy of the weight at its starting height would be PE = mgh. And KE = 1/2mv2. So Total energy, E = 1/2mv2 + mgh.

How would vx and vy be calculated, though, I'm not sure?
 
Sounds like a fun project. Vx and Vy are constrained by the hinge and rigid rod. The velocity vector will always be along the path of the weight, so around in a circle centered on the hinge (if I understood your explanation correctly). Just use the triangle formed by the hinge, the weight, and the point directly below the weight on the horizontal surface to give you the angles you need to use some trig to calulate Vx and Vy from Vtangential.
 
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