Forces and Pulleys of two blocks

AI Thread Summary
The discussion revolves around a physics problem involving two blocks connected by a rope over pulleys, with weights of 412N and 908N. The key questions focus on calculating the acceleration of the lighter block and understanding the difference in acceleration when the heavier block is removed and a downward force is applied. Participants suggest drawing force diagrams to clarify the forces acting on each block. To solve the problem, it's recommended to apply Newton's second law (F = ma) for both blocks and eliminate tension from the equations. The conversation emphasizes the importance of visualizing forces to tackle such problems effectively.
Cheddar
Messages
38
Reaction score
0

Homework Statement


Two blocks are connected by a rope that passes over a set of pulleys. One block has a weight of 412N and the other has a weight of 908N. The rope and the pulleys are massless and there is no friction. (a) What is the acceleration of the lighter block? (b) Suppose that the heavier block is removed, and a downward force of 908N is provided by someone pulling on the rope. Find the acceleration of the remaining block. (c) Why are the answers in (a) and (b) different?

Homework Equations


weight = mass * acceleration(gravity)


The Attempt at a Solution


So mass = 42.0 kg for the smaller black and mass = 92.7 kg for the larger block.
This is as far as I get.
 
Physics news on Phys.org
***NOT AN EXPERT***

If I were you, I would draw a force diagrams for each block. These kinds of problems can get really confusing if you don't sort out what forces are going where.
 
Cheddar said:
Two blocks are connected by a rope that passes over a set of pulleys. One block has a weight of 412N and the other has a weight of 908N. The rope and the pulleys are massless and there is no friction. (a) What is the acceleration of the lighter block?

Hi Cheddar! :smile:

Call the tension T, do two F = ma equations, one for each block, and then eliminate T. :wink:
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top