- #71

Erdi

- 37

- 6

I could replace this with another expression. I see what you meanerobz said:

So i solved for

2*a(m1) = -(a(M)+a(m2)), and so i found expression for a(M,m2)

2*a(m1) =-(g-(T2/M) + g-(T2/m2))

Replacement:

2*a(m1) =-(2g-(T1/2) * ((1/M) + (1/m2)), T1 = m1g - m1a

2*a(m1) = -(2*g - (m1/2) * (g-a(m1)) * ((1/M)+(1/m2))