Forces and reaction forces generated by a linear actuator

AI Thread Summary
A linear actuator generates a force of 10N while wedged between two solid walls. The participants discuss the magnitudes of the forces in the system, concluding that if the actuator's force is 10N, then F1, F2, R1, and R2 should all equal 5N. This is based on the principle of equilibrium, where the forces must balance. The conversation emphasizes the importance of understanding how reaction forces relate to the applied force in a confined system. Overall, the consensus is that the forces are evenly distributed in this scenario.
amrbekhit
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A linear actuator is wedged between two solid walls as shown in the diagram below. The linear actuator is pushing outwards with a force of 10N. What are the magnitudes of the forces labelled in the diagrams?

linearactuatorfreebodydiagram.png


I reckon that F1 = F2 = R1 = R2. However, I'm not sure if F1 = F2 = 5N or 10N. I'm guessing 10N.

Any thoughts?

--Amr
 
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If the system is in equilibrium then all the forces are balanced.

Remember, if R1 = 10N and R2 = 10N that implies that there is 20N compressing the system and we know there is only 10N expanding it.

Jared
 
Hi Jared,

Thanks for your reply. Based on that, if the linear actuator produces a 10N force, F1 = F2 = R1 = R2 = 5N.

Amr
 
I'd agree with that conclusion.

Jared
 

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