- #1
Brittany W
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Homework Statement
http://imgur.com/a/Bz6PR
Homework Equations
The Attempt at a Solution
I included my attempt in the picture
AI Thread Summary
The discussion revolves around a homework problem involving forces, specifically focusing on calculating tension. The original tension value of 11,000 N is questioned, as it is no longer applicable in part b of the problem. A user attempts to derive the tension using the equation T=384Sin(7) but finds their answer significantly off. They seek clarification on how to properly arrive at this equation. The conversation emphasizes the need for a clear understanding of the forces involved in the problem.
http://imgur.com/a/Bz6PR
I included my attempt in the picture
- #2
TSny
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In part b, the tension is the unknown force. The tension is no longer 11000 N.
- #3
Brittany W
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so then T=384Sin(7)? I tried doing this to a similar problem with different numbers since I had the answer on hand, but my answer was still WAY off.TSny said:
- #4
TSny
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Can you explain how you got this equation?Brittany W said:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Figure 1 Overall Structure Diagram
Figure 2: Top view of the piston when it is cylindrical
A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N.
Figure 3: Modifying the structure to incorporate a fixed internal piston
When I modify the piston...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
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