**Part 1**

**1. The only two forces acting on a body have magnitudes of 20 N and 42 N and directions that differ by 60°. The resulting acceleration has a magnitude of 20 m/s2. What is the mass of the body?**

**2. F=ma**

**3. Im not sure how to solve this because i'm used to being able to use trig like cos and tan, but this problem doesn't create a triangle with 90 degrees**

----------------------------------------------------------------------------------------------------------------------------------

**Part 2**

**1. A bullet of mass 6.5*10-3 kg moving at 1150 m/s impacts with a large fixed block of wood and travels 8 cm before coming to rest. Assuming that the deceleration of the bullet is constant, find the force exerted by the wood on the bullet.**

**2. F=ma**

V^2=Vi^2+2ax

V^2=Vi^2+2ax

**3. V=0 Vi=1150 m/s x=.08 m solve for a and i got -8265625 m/s^2 then multiply by mass (6.5E-3) and get -53726.5625. Is this right? would i void the negative on a force?**

Last edited: