How Does the Leftmost Block Affect the Middle Block in a Force Chain?

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The discussion focuses on the interaction between three blocks of different masses when a 12 N force is applied to the leftmost block. The acceleration of the system is calculated to be 2 m/s² using the formula F=ma. The leftmost block exerts a force of 8 N on the middle block, but the initial calculation was incorrect due to not accounting for the opposing force from the rightmost block. The net force acting on the middle block includes contributions from both the leftmost and rightmost blocks. Understanding these forces is crucial for accurately determining the dynamics of the system.
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Homework Statement


Blocks of 1.0, 2.0, and 3.0 kg blocks are lined up on a table (1kg block being on the left, 2kg in the middle, 3kg being on the right). A rightward poiting 12 N force is applied to the leftmost block. What force does the leftmost block exert on the middle one?


Homework Equations



F=ma
a= Force applied / (m1 + m2 +m3)
a= 12N/6k= 2m/s^2

The Attempt at a Solution


Ok so this is what I did:

12N + F(1on2)=(mass of 2nd block)(acceleration)
12+F(1on2)=(2kg)(2m/s^2)
F(1on2)=8N, I got this wrong. Did i miss something, or should this force actually be negative.
 
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You got he acceleration right and that is good.

The 1 kg block exerts a force on the middle block that is to the right. The 3 kg block exerts a force on the the 2 kg block that is to the left. You don't have that one. Added together these forces are the net force on the 2 kg block.
 

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